Exemple de post http simple en Objective-C ?

Question

J'ai une page Web en php qui nécessite une connexion (identifiant et mot de passe). L'utilisateur entre les informations dans l'application sans problème, mais j'ai besoin d'un exemple sur la façon de faire une demande POST à un site Web. L'exemple d'apple sur le site d'assistance est plutôt compliqué et montre un téléchargement d'image le mien devrait être plus simple Je veux juste poster 2 lignes de texte Quelqu'un a-t-il de bons exemples ?

Alex

Answer 1

C'est ce que j'ai utilisé récemment, et cela a bien fonctionné pour moi :

NSString *post = @"key1=val1&key2=val2";
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:@"http://www.nowhere.com/sendFormHere.php"]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

---

Tiré à l'origine de http://deusty.blogspot.com/2006/11/sending-http-get-and-post-from-cocoa.html mais ce blog ne semble plus exister.

Answer 2

Extrait du site officiel d'Apple :

// In body data for the 'application/x-www-form-urlencoded' content type,
// form fields are separated by an ampersand. Note the absence of a
// leading ampersand.
NSString *bodyData = @"name=Jane+Doe&address=123+Main+St";

NSMutableURLRequest *postRequest = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"https://www.apple.com"]];

// Set the request's content type to application/x-www-form-urlencoded
[postRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

// Designate the request a POST request and specify its body data
[postRequest setHTTPMethod:@"POST"];
[postRequest setHTTPBody:[NSData dataWithBytes:[bodyData UTF8String] length:strlen([bodyData UTF8String])]];

// Initialize the NSURLConnection and proceed as described in
// Retrieving the Contents of a URL

De : code avec chris

    // Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://google.com"]];

// Specify that it will be a POST request
request.HTTPMethod = @"POST";

// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

// Convert your data and set your request's HTTPBody property
NSString *stringData = @"some data";
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;

// Create url connection and fire request
NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];

Answer 3

ASIHTTPRequest rend la communication en réseau très facile

ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request addPostValue:@"Ben" forKey:@"names"];
[request addPostValue:@"George" forKey:@"names"];
[request addFile:@"/Users/ben/Desktop/ben.jpg" forKey:@"photos"];
[request addData:imageData withFileName:@"george.jpg" andContentType:@"image/jpeg" forKey:@"photos"];

Answer 4

Vous pouvez le faire en utilisant deux options :

Utilisation de NSURLConnection :

NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
request.HTTPMethod = @"POST";
// Form URL-Encoded Body

NSDictionary* bodyParameters = @{
    @"username": @"reallyrambody",
    @"password": @"123456"
};
request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];

// Connection

NSURLConnection* connection = [NSURLConnection connectionWithRequest:request delegate:nil];
[connection start];

/*
 * Utils: Add this section before your class implementation
 */

/**
 This creates a new query parameters string from the given NSDictionary. For
 example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
 string will be @"day=Tuesday&month=January".
 @param queryParameters The input dictionary.
 @return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
    NSMutableArray* parts = [NSMutableArray array];
    [queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
        NSString *part = [NSString stringWithFormat: @"%@=%@",
            [key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
            [value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
        ];
        [parts addObject:part];
    }];
    return [parts componentsJoinedByString: @"&"];
}

/**
 Creates a new URL by adding the given query parameters.
 @param URL The input URL.
 @param queryParameters The query parameter dictionary to add.
 @return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
    NSString* URLString = [NSString stringWithFormat:@"%@?%@",
        [URL absoluteString],
        NSStringFromQueryParameters(queryParameters)
    ];
    return [NSURL URLWithString:URLString];
}

Utilisation de NSURLSession

- (void)sendRequest:(id)sender
{
    /* Configure session, choose between:
       * defaultSessionConfiguration
       * ephemeralSessionConfiguration
       * backgroundSessionConfigurationWithIdentifier:
     And set session-wide properties, such as: HTTPAdditionalHeaders,
     HTTPCookieAcceptPolicy, requestCachePolicy or timeoutIntervalForRequest.
     */
    NSURLSessionConfiguration* sessionConfig = [NSURLSessionConfiguration defaultSessionConfiguration];

    /* Create session, and optionally set a NSURLSessionDelegate. */
    NSURLSession* session = [NSURLSession sessionWithConfiguration:sessionConfig delegate:nil delegateQueue:nil];

    /* Create the Request:
       Token Duplicate (POST http://www.example.com/path)
     */

    NSURL* URL = [NSURL URLWithString:@"http://www.example.com/path"];
    NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:URL];
    request.HTTPMethod = @"POST";

    // Form URL-Encoded Body

    NSDictionary* bodyParameters = @{
        @"username": @"reallyram",
        @"password": @"123456"
    };
    request.HTTPBody = [NSStringFromQueryParameters(bodyParameters) dataUsingEncoding:NSUTF8StringEncoding];

    /* Start a new Task */
    NSURLSessionDataTask* task = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
        if (error == nil) {
            // Success
            NSLog(@"URL Session Task Succeeded: HTTP %ld", ((NSHTTPURLResponse*)response).statusCode);
        }
        else {
            // Failure
            NSLog(@"URL Session Task Failed: %@", [error localizedDescription]);
        }
    }];
    [task resume];
}

/*
 * Utils: Add this section before your class implementation
 */

/**
 This creates a new query parameters string from the given NSDictionary. For
 example, if the input is @{@"day":@"Tuesday", @"month":@"January"}, the output
 string will be @"day=Tuesday&month=January".
 @param queryParameters The input dictionary.
 @return The created parameters string.
*/
static NSString* NSStringFromQueryParameters(NSDictionary* queryParameters)
{
    NSMutableArray* parts = [NSMutableArray array];
    [queryParameters enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
        NSString *part = [NSString stringWithFormat: @"%@=%@",
            [key stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding],
            [value stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
        ];
        [parts addObject:part];
    }];
    return [parts componentsJoinedByString: @"&"];
}

/**
 Creates a new URL by adding the given query parameters.
 @param URL The input URL.
 @param queryParameters The query parameter dictionary to add.
 @return A new NSURL.
*/
static NSURL* NSURLByAppendingQueryParameters(NSURL* URL, NSDictionary* queryParameters)
{
    NSString* URLString = [NSString stringWithFormat:@"%@?%@",
        [URL absoluteString],
        NSStringFromQueryParameters(queryParameters)
    ];
    return [NSURL URLWithString:URLString];
}

Answer 5

Je suis un débutant en matière d'applications iPhone et j'ai toujours un problème bien que j'aie suivi les conseils ci-dessus. Il semble que les variables POST ne soient pas reçues par mon serveur - je ne sais pas si cela vient du code php ou objective-c ...

la partie objectif-c (codée selon la méthode du protocole de Chriso)

// Create the request.
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://example.php"]];

// Specify that it will be a POST request
request.HTTPMethod = @"POST";

// This is how we set header fields
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

// Convert your data and set your request's HTTPBody property
NSString *stringData = [NSString stringWithFormat:@"user_name=%@&password=%@", self.userNameField.text , self.passwordTextField.text];
NSData *requestBodyData = [stringData dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPBody = requestBodyData;

// Create url connection and fire request
//NSURLConnection *conn = [[NSURLConnection alloc] initWithRequest:request delegate:self];
NSData *response = [NSURLConnection sendSynchronousRequest:request
                                         returningResponse:nil error:nil];

NSLog(@"Response: %@",[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]);

En dessous de la partie php :

if (isset($_POST['user_name'],$_POST['password'])) 

{

// Create connection
$con2=mysqli_connect($servername, $username, $password, $dbname);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
else 
{
// retrieve POST vars
$username = $_POST['user_name'];
$password = $_POST['password'];

$sql = "INSERT INTO myTable (user_name, password) VALUES ('$username',   '$password')";
$retval = mysqli_query( $sql, $con2 );
if(! $retval )
{
die('Could not enter data: ' . mysql_error());
}
echo "Entered data successfully\n";

mysqli_close($con2);

}
}
else
{
echo "No data input in php";
}

J'ai été bloqué ces derniers jours sur celui-ci.