Je l'utiliser...mais n'avez jamais fait de toute métro de développement d'applications, donc je ne connais pas de restrictions sur les bibliothèques offrent à vous. (notez que vous aurez besoin de marquer vos classes avec les attributs DataContract et DataMember)
public static class JSONSerializer<TType> where TType : class
{
/// <summary>
/// Serializes an object to JSON
/// </summary>
public static string Serialize(TType instance)
{
var serializer = new DataContractJsonSerializer(typeof(TType));
using (var stream = new MemoryStream())
{
serializer.WriteObject(stream, instance);
return Encoding.Default.GetString(stream.ToArray());
}
}
/// <summary>
/// DeSerializes an object from JSON
/// </summary>
public static TType DeSerialize(string json)
{
using (var stream = new MemoryStream(Encoding.Default.GetBytes(json)))
{
var serializer = new DataContractJsonSerializer(typeof(TType));
return serializer.ReadObject(stream) as TType;
}
}
}
Donc, si vous avez eu une classe comme ça...
[DataContract]
public class MusicInfo
{
[DataMember]
public string Name { get; set; }
[DataMember]
public string Artist { get; set; }
[DataMember]
public string Genre { get; set; }
[DataMember]
public string Album { get; set; }
[DataMember]
public string AlbumImage { get; set; }
[DataMember]
public string Link { get; set; }
}
Alors que vous pouvez l'utiliser comme ça...
var musicInfo = new MusicInfo
{
Name = "Prince Charming",
Artist = "Metallica",
Genre = "Rock and Metal",
Album = "Reload",
AlbumImage = "http://up203.siz.co.il/up2/u2zzzw4mjayz.png",
Link = "http://f2h.co.il\/7779182246886"
};
// This will produce a JSON String
var serialized = JSONSerializer<MusicInfo>.Serialize(musicInfo);
// This will produce a copy of the instance you created earlier
var deserialized = JSONSerializer<MusicInfo>.DeSerialize(serialized);