J'ai écrit un petit programme d'exemple pour tester cela avec la réponse de David. Vous devrez créer une base de données Access et créer manuellement le DBML pour Linq-to-SQL, car vous ne pouvez pas les glisser-déposer.
Les inserts échouent, citant Missing semicolon (;) at end of SQL statement.
mais les requêtes semblent fonctionner correctement.
using System;
using System.Collections.Generic;
using System.Data.OleDb;
using System.IO;
using System.Linq;
using Linq2Access.Data;
namespace Linq2Access
{
class Program
{
static readonly string AppPath = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location);
static readonly string DbPath = Path.Combine(AppPath, "Data", "database.accdb");
static readonly string DbConnString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source='" + DbPath + "';Persist Security Info=False;";
static void Main(string[] args)
{
if (!File.Exists(DbPath))
throw new Exception("Database file does not exist!");
using (OleDbConnection connection = new OleDbConnection(DbConnString))
using (DataRepositoryDataContext db = new DataRepositoryDataContext(connection))
{
List<dbProject> projects = new List<dbProject>();
for (int i = 1; i <= 10; i++)
{
dbProject p = new dbProject() { Title = "Project #" + i };
for (int j = 1; j <= 10; j++)
{
dbTask t = new dbTask() { Title = "Task #" + (i * j) };
p.dbTasks.Add(t);
}
projects.Add(p);
}
try
{
//This will fail to submit
db.dbProjects.InsertAllOnSubmit(projects);
db.SubmitChanges();
Console.WriteLine("Write succeeded! {0} projects, {1} tasks inserted",
projects.Count,
projects.Sum(x => x.dbTasks.Count));
}
catch(Exception ex)
{
Console.WriteLine("Write FAILED. Details:");
Console.WriteLine(ex);
Console.WriteLine();
}
try
{
//However, if you create the items manually in Access they seem to query fine
var projectsFromDb = db.dbProjects.Where(x => x.Title.Contains("#1"))
.OrderBy(x => x.ProjectID)
.ToList();
Console.WriteLine("Query succeeded! {0} Projects, {1} Tasks",
projectsFromDb.Count,
projectsFromDb.Sum(x => x.dbTasks.Count));
}
catch (Exception ex)
{
Console.WriteLine("Query FAILED. Details:");
Console.WriteLine(ex);
Console.WriteLine();
}
Console.WriteLine();
Console.WriteLine("Press any key to continue...");
Console.ReadKey();
}
}
}
}
0 votes
Avez-vous trouvé un fournisseur pour travailler avec ACCESS ?
1 votes
Non, j'ai juste décidé de le faire de la manière ennuyeuse sans LINQ to SQL.